Avery long ladder 40 feet long, rests against a vertical wall. suppose that the base of the ladder slides away from the wall at a rate of 5 ft/sec. how fast is the top of the ladder sliding down the wall when the bottom of the ladder is 24 feet from the wall? assume that the top of the ladder remains in contact with the wall.

3.75 ft/s

Explanation:

Given

Length of ladder(L)=40 feet

base of ladder moves at a rate of 5 ft/sec

Bottom of ladder from wall(x)=24 feet

let horizontal distance be x and vertical distance be y

therefore

 from Pythagoras

differentiate

negative sign indicates height is decreasing

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.