Ahorizontal circular turntable rotates about its center at the uniform rate of 10.9 revolutions per minutes. find the greatest distance (in meter) from the center at which a small block will remain stationary relative to the turn table. the coefficient of static friction between the turntable and the object is 0.8.

6.03 m

Explanation:

First of all, let's convert the angular velocity from revolutions per minute to radians per second:

The frictional force on the block ranges from zero to a maximum value of

In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:

where

m is the mass of the block

is the angular velocity

r is the distance of the block from the centre

is the coefficient of static friction

g = 9.8 m/s^2

Solving for r, we find:

as a general rule, scissors have blades less than 6 in (15 cm) long and usually have handles with finger holes of the same size. shears have blades scissors used to cut hair or fabric must be much sharper

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6