An infinite nonconducting sheet has a surface charge density σ = 0.10 µc/m2 on one side. how far apart are equipotential surfaces whose potentials differ by 86 v?

d = 0.152 meters                                                        

Explanation:

It is given that,

Surface charge density of the sheet,

Potential, V = 86 V

We know that the electric field due to the non conducting sheet is given by :

Also, the relation between the electric field and electric potential is given by :

d is the distance between equipotential surfaces

d = 0.152 meters

So, the equipotential surfaces are separated by 0.152 meters. Hence, this is the required solution.

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