Compute your average velocity in the following two cases: (a) you walk 73.2m at a speed of 1.22m/s and then run 7302m at a soeed of 3.05 m/s along a stright track. (b) you walk for 1.00min at a speed of 1.22m/s and then run for 1.00 at 3.05m/s along a stright track. (c) graph x verses t for both cases and indicate how the average velocity is found on the graph

a) 3.00 m/s, approximately and b) 2.135 m/s

Explanation:

a) x1 = 73.2 m and v1 = 1.22 m/s, then

;

x2 = 7302 m and v2 = 3.05 m/s, then

.

So the average speed is

.

b) t1 = 60 s and v1 = 1.22 m/s, then

;

t2 = 60 s and v2 = 3.05 m/s, then

;

So the average speed is

.

c) Plot cumulative distance Vs. cumulative time, the slope of the line going through the origen and the final coordinate, is the velocity

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation: