Create a state machine that recognizes the bit sequence "001". it will read a single bit at a time. it always outputs a logic 0 until after it has seen the "001" sequence, then it outputs a 1 a) draw the truth table for the input bit, current state bits, next state bits, and output bit. (6pts) b) use karnaugh maps to find minimal boolean equations that describe the next state bits and output bit. (3bits x 3pts 9pts) c) create a circuit in logicworks using simulation gates and d flip flops that implements the state machine. you may use the cell "d flip flop" provided in the "simulation logic" library. attach switches to the inputs and probes to the output (5pts)

Where is the table ? you can take a picture of it

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Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

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