If pressure is increased from 200 kpa to 300 kpa, and the original volume of gas was 1.5 l, what is the new volume? assume the temperature and number of particles are constant.
a. 0.5 l
b. 1 l
c. 2 l
d. 3 l

The answer to your question is:      V2 = 1 l

Explanation:

Data

P1 = 200 kPa

P2 = 300 kPa

V1 = 1.5 l

V2 = ?

Formula

                          P1V1 = P2V2

                          V2 = (P1V1) / P2

                          V2 = (200 x 1.5) / 300

                          V2 = 1 l