Two current-carrying wires are parallel to each other. the current in one is increased by a factor of 2 , the current in the other is increased by a factor of 3 , and the distance between the wires is decreased by a factor of 13 . what is the change in the force between the wires?

the new force is 78 times higher that the initial force before made the changes.

Explanation: In order to solve this problem we have to take into account the following expression for the force ( per length ) between currents, which is given by:

F/L=(μo*I1*I2)/(2*π*r) where μo is the magnetic permeability of vaccum and r is the distance between conductors. I1 and I2 are the currents.

Considering that I1 and I2 are increased a factor 2 and 3 , respectively,

Also considering that r is decreased by a factor of 13

The new force per Length is:

F/L=(μo*2*I1*3*I2)/(2*π*r/13) reorganising  the terms, we have

F/L=13*6 (μo*I1*I2)/(2*π*r)=78*F/L=(μo*I1*I2)/(2*π*r)=78* F/L initial

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles

the ima (higher than 1m) will be greater than the ima with the height of 1m.