Arocket is far away from all planets and stars, so gravity isnot a consideration. it is using its rocket engines to accelerateupward with an acceleration a=9.80 m/s^2
on the floor of the main deck is a crate(object with brickpattern) with a mass of 75.0kg.
determine the normal force the crate would experience if itwere at rest on the surface of the earth.

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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