Amodel rocket is launched straight upward with an initial speed of 56.5 m/s. it accelerates with a constant upward acceleration of 1.96 m/s 2 until its engines stop at an altitude of 198.8 m. what is the maximum height reached by the rocket? answer in units of m.

Maximum height reached by the rocket, h = 202.62 meters            

Explanation:

It is given that,

Initial speed of the model rocket, u = 56.5 m/s

Constant upward acceleration,

Distance traveled by the engine until it stops, d = 198.8 m

Let v is the speed of the rocket when the engine stops. It can be calculated using the third equation of motion as :

v = 63.02 m/s

At the maximum height, v = 0 and the engine now decelerate under the action of gravity, a = -g. Let h is the maximum height reached by the rocket.

Again using third equation of motion as :

h = 202.62 meters

So, the maximum height reached by the rocket is 202.62 meters. Hence, this is the required solution.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

what is the actual question though?