Apositively charged particle moves through an electric field. as part of a complicated trajectory, the particle passes through the points a and b. the electric potential of the two points is such that vb > va. the electric force is the only force acting on the particle. what can be deduced about the speed, v, of the particle at the two points?

(a) the speed is equal at the two points.
(b) the speed is larger at a than at b.
(c) the speed is larger at b than at a.

(B) The speed is larger at A than at B.

Explanation:

Point B, the final point of the trajectory, has higher electric potential than point A, the initial point of the trajectory, so the electric potential energy of the charged particle increases, which means that its kinetic energy must be decreasing, thus the speed at B must be lower than the speed at A.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force