Determine the maximum hauling production given the following conditions. as many scrapers as required can be used, but only one push tractor will be available. the material is a sandy clay (dry earth), 3,200 lb/bcy. the expected haul-road rolling resistance is 80 lb/ton. the average scraper load will be 28.2 lcy. the haul route has three segments: 700 ft at a grade of + 5%; 2,500 ft at + 2% grade; and 500 ft at - 2% grade (moving from the cut to the fill). to account for acceleration and deceleration, use an average speed of 5 mph for 200 ft at each end of the haul and

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

happy to

pls mark as brainliest.

80cm/s.

24cm/s.

53.3cm/s.

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.