Apositive charge is moved from point a to point b along an equipotential surface. how much work is performed or required in moving the charge? a positive charge is moved from point a to point b along an equipotential surface. how much work is performed or required in moving the charge? work is required in moving the positive charge from point a to point b. no work is performed or required in moving the positive charge from point a to point b. work is performed in moving the positive charge from point a to point b. work is both performed and required in moving the charge from point a to point b. submitrequest answer provide feedback next

No work is performed or required in moving the positive charge from point A to point B.

Explanation:

Lets take

Q= Positive charge which move from  point A to point B along

Voltage difference,ΔV =V₁ - V₂  

The work done

W = Q . ΔV

Given that  charge is moved from point A to point B along an equipotential surface.It means that voltage  difference is zero.

ΔV = 0

So

W = Q . ΔV

W = Q x 0

W= 0 J

So work is zero.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.