Aproton enters a uniform magnetic field of strength 2 t at 300 m/s. the magnetic field is oriented perpendicular to the proton’s velocity. what is the magnitude of the force that the proton experiences while it moves through the magnetic field?

Magnetic force,

Explanation:

It is given that,

Magnetic field, B = 2 T

Velocity of the proton, v = 300 m/s

Charge on the proton,

The magnetic field is oriented perpendicular to the proton’s velocity. The magnetic force on the charged particle is given by :

The magnetic field is oriented perpendicular to the proton’s velocity,

So, the magnitude of the force that the proton experiences while it moves through the magnetic field is . Hence, this is the required solution.

answer: decibel

explanation: