Awater pump pumps 3 kg of water every second from the bottom of a well to the top of the well 50 m above. if the pump uses 2000 w of electrical power to accomplish the task, what is the efficiency of the pump

70%

Explanation:

Power = work / time

P = mgh / t

P = (3 kg) (9.8 m/s²) (50 m) / (1 s)

P = 1470 W

Efficiency = power out / power in

e = 1470 W / 2000 W

e = 0.735

The efficiency of the pump is 0.735, or 73.5%.

Rounded to one significant figures, the efficiency is 0.7, or 70%.

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energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this