3. high speed strobe light photographs show the head of a 215 g golf club traveling at 55 m/s just before it strikes a 46
golf ball at rest on a tee. after the collision, the club travels in the same direction at 42 m/s. use the law of conservati
of momentum to find the speed of the golf ball just after impact.

the conservation of the momentum allows to find the the result for the speed of the golf ball after the stroke is:

        v = 60.8 m / s

Given parameters

To find

Momentum is defined by the product of mass and velocity.

        p = m v

Where me is the mass and v the velocity of the body.

In an isolated system the forces are internal, therefore the momentum is conserved.

Let's write the momentum in two moments:

Initial instant. Before hit.

        p₀ = M v₁ + 0

Final instatne. After the coup.

        p_f = M v₂ + m v

If we define the system as formed by the golf club and the golf ball, this system is isolated and the momentum is conserved.

         p₀ = p_f

         M v₁ = M v₂ + m v

         v =  

Let's calculate

         v =  

         v = 60.75 m / s

In conclusion, using the conservation of momentum, we can find tfor the speed of the golf ball after the stroke is:

        v = 60.8 m / s

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61 m/s

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(215 g) (55 m/s) + (46 g) (0 m/s) = (215 g) (42 m/s) + (46 g) v

v ≈ 61 m/s

b.

hope this : )

the answer would be a