Two waves on identical strings have frequencies in a ratio of 2 to 1. if their wave speeds are the same, then how do their wavelengths compare?

λ1=λ2/2 (ν1= 2*ν2)

Explanation: In order to explain this problem we have to use following  expression for waves.

v=λ*ν ; v is the wave speed. λ and ν are the wavelength and frequency of the wave, respectively.

we have two waves where ν1= 2*ν2 then as the speed is the same for both waves, we have,

λ1*ν1=λ2*ν2  with ν1= 2*ν2 then

λ1=λ2*ν2/v1=λ2*ν2/(2*ν2)= λ2/2

λ1=λ2/2

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

b. a lightning bug, plug of grass, and a worm