Ahollow, conducting sphere with an outer radius of 0.240 m and an inner radius of 0.200 m has a uniform surface charge density of +6.67 × 10^−6 c/m^2. a charge of -0.600 μc is now introduced into the cavity inside the sphere. calculate the strength of the electric field at a distance 0.11 m from the center of the sphere.

446.28*10^3 N/C ( directed to center of the sphere)

Explanation: In order to explain this problem we have to use the electric field expression, which is given by:

E=k*q/r^2 where k is a constant equal 9*10^9 N/C^2*m^2, r is the distance from the charge to calculate the electric field.

Then we have,

E=(9*10^9*0.6*10^-6)/(0.11)^2= 446.28*10^3 N/C

Due to the negative point charge, the electric field is directed to the center of the sphere.