Atrain moving with a velocity of 42.9 km/hour north, increases its speed with a uniform acceleration of 0.250 m/s^2 north until it reaches a velocity of 160.0 km/hour north. what distance did the train travel while it was increasing its velocity, in units of meters? give the answer as a positive number

3658.24m

Explanation:

Hello!

the first thing that we must be clear about is that the train moves with constant acceleration

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf = final speed =160km/h=44.4m/s

Vo = Initial speed =42.9km/h=11.92m/s

A = acceleration =0.25m/s^2

X = displacement

solving

the distance traveled by the train is 3658.24m

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explanation:

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered