A120 v, 60 hz power source is connected in series across an 800 ω resistance and an unknown capacitance in series. the voltage drop across the resistor is 102 v. find (a) the voltage drop across the capacitor; and (b) the reactance of the capacitor.

a)Vc= 63.21 V

b)Xc= 495.756  Ω

Explanation:

Assume that voltage across the resistance is Vr and capacitor Vc

So

Now by putting the values

Vc= 63.21 V

We know that for resistance

Vr= I R

102 = I x 800

I=0.1275 A

Let reactance of capacitor is Xc

So

Vc= Xc . I

63.21 = 0.1275 x Xc

Xc= 495.756  Ω

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.

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