Acoin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (4.0 m, 5.8 m) while a constant force acts on it. the force has magnitude 1.3 n and is directed at a counterclockwise angle of 121° from the positive direction of the x axis. how much work is done by the force on the coin during the displacement?

i understand that w=fd and f=ma

w=1.3*d, but im not quite sure how exactly to find displacement.

Work done, W = 3.78 Joules

Explanation:

It is given that,

Displacement in x-y coordinate,

Magnitude of force, F = 1.3 N

The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.

Firstly, finding the vector form of force as :

The work done is given by :

W = 3.78 Joules

So, the work done by the force is 3.78 Joules. Hence, this is the required solution.

current flows in a wire

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.