Adoubly ionized molecule (i. e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.31×10−16 n as it moves at 265 m/s at 69.1∘ to the direction of the field. find the magnitude of the magnetic field. t

So magnetic field will be 0.0067 T

Explanation:

We have given that molecule is doubly ionized

So charge

Magnetic force is given by F =

velocity is given as v = 265 m/sec

Angle

We know that magnetic force is given by

the answer is a. at the equator

the answer would be   dignified - apex