Aboy exerts a 36-n horizontal force as he pulls a 52-n sled across a cement sidewalk at a constant speed. what is the coefficient of kinetic friction between the sidewalk and the metal sled runners? ignore air resistance.

0.69

Explanation:

Sum of the forces on the sled in the y direction:

∑F = ma

Fn - 52 N = 0

Fn = 52 N

Sum of the forces on the sled in the x direction:

∑F = ma

36 N - Fn μ = 0

Fn μ = 36 N

μ = 36 N / Fn

Substitute:

μ = 36 N / 52 N

μ = 0.69

cofficient of kinetic friction is 0.6923

Explanation:

Given Data

Coefficient of kinetic friction  μk = /N where fk is force of kinetic friction and N is normal reaction;

we have N = 52 N, and fk = 36 N ;

                μk = /N

                      = 36/52

                      = 0.6923

    cofficient of kinetic friction is 0.6923.

answer would be d.) i hope this

explanation: