Asilver wire 2.6 mm in diameter transfers a charge of 420 cin 80 min. silver contains 5.8 \times 10^{28} free electrons per cubic meter. what is the current in the wire? what is the magnitude of the drift velocity of the electronsin the wire?

The current in the wire is 0.0875 A and the drift velocity of the electrons in the wire is 1.77x10^{-6} m/s.

Explanation:

Facts that you know from the problem statement:  

Using the diameter of the wire the radius is r=d/2. r=2.6/2= 1.3 mm. It is useful to have the time in seconds so t=80 min = 4800 s. You know the charge Q= 420 C. The concentration of electrons in the wire is n = 5.8*10^{28}.

The current in the wire is the net charge that flows through the area in a second, the units are amperes (A), and it is given by:

Replace the values:

The drift velocity in the electrons in the wire (V) is given by the equation:

Replace the values that you have and the charge of an electron taht is equal to 1.6*10^{-19}

V=1.77x10^{-6} m/s

massxgravity x heght=weightxheight= pe

4900=490xh

h=10