Asoap-box derby race car sits on the starting ramp. the ramp is elevated at an angle of 8.5 degrees. the angle between the gravity vector and the ramp surface is a . the force of gravity on the car is 1225 n. the normal force of the track on the car is 1210 n. the frictional force of the track on the car is 15.2 n. what is the net force on the car?

Explanation:

given,

angle of inclination with the horizontal = 8.5°

force of gravity = 1225 N

normal force on car  = 1210 N

frictional force = 15.2 N

net force = ?

equating horizontal forces

F_x = -165.87 N

equating vertical forces

F_y = -1.54 N

net force

it may be wrong but i think its a

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day