Energy is required to move a 657 kg mass from the earth’s surface to an altitude 2.97 times the earth’s radius re. what amount of energy is required to accomplish this move? the acceleration of gravity near the earth is9.8 m/s 2 , the mass of the earth is 5.98 × 1024 kg , and the radius of the earth is 6.37 × 106 m . answer in units of j.

 U = - 1,385 10¹⁰ J

Explanation:

To calculate the energy of that movement we can use the expression for gravitational potential energy, derived from the law of universal gravitation

            U = - G m1 M / r

Where zero is taken at an infinite distance

We can substitute and calculate

              r = 2.97 Re

             U = - 6.67 10⁻¹¹ 5.98 10²⁴ 657 /(2.97 6.37 10⁶)

             U = - 1,385 10¹⁰ J

This is a very large energy value.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

answer a fan shaped mass of sediment deposited at the base of a mountain front do to an abrupt change in stream gradient;