Asatellite has a mass of 5832 kg and is in a circular orbit 4.13 × 105 m above the surface of a planet. the period of the orbit is 1.9 hours. the radius of the planet is 4.38 × 106 m. what would be the true weight of the satellite if it were at rest on the planet’s surface?

W = 28226.88 N

Explanation:

Given,

Mass of the satellite, m = 5832 Kg

Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m

The time period of the orbit, T = 1.9 h

                                            = 6840 s

The radius of the planet, R = 4.38 x 10⁶ m

The time period of the satellite is given by the formula

                               second

Squaring the terms and solving it for 'g'

                             g = 4 π²   m/s²

Substituting the values in the above equation

                   g = 4 π²  

                                    g = 4.84 m/s²      

Therefore, the weight

                                     w = m x g   newton

                                         = 5832 Kg x 4.84 m/s²

                                         = 28226.88 N

Hence, the weight of the satellite at the surface, W = 28226.88 N                

6/12=1/2

step-by-step explanation:

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be