Aproton is confined in a uranium nucleus of radius 7.2x10-15 m. determine the proton’s minimum kinetic energy according to the uncertainty principle if the proton is confined to a 1 dimensional box that has the length of the nuclear diameter. you can assume that the velocities involve are non-relativistic, so that ekin=p2 /(2m).

  K = 16.1 10⁻¹⁵ J

Explanation:

The equation for the uncertainty principle establishes the relationship between the medical minimum that can simultaneously perform the position and momentum of a particle.

      ΔxΔp> = (h/2π) / 2

Let's calculate the variation of the moment

     Δp> = (h/2π) / 2 Δx  

     Δp> = 6.63 10⁻³⁴ / (4π  7.2 10⁻¹⁵)

     Δp = 7.33 10⁻²¹ m / s

Let's calculate the kinetic energy

     K = p² / 2m

     K = (7.33 10⁻²¹)² /2 1.67 10⁻²⁷

     K = 16.1 10⁻¹⁵ J

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

f=ma newton

f=100x2.5=250n