Iwatched an astronaut drop a feather one the moon. it took 1.3 seconds. how fast was it going right before it hit the lunar surface if freefall acceleration on the moon is 1.62 m/s^2?

The final velocity of feather, v = 2.106 m/s

Explanation:

Given that,

The initial velocity of the feather, u = 0 m/s

Freefall acceleration of the moon, a = 1.62 m/s²

Time taken by the feather to reach the lunar surface is, t = 1.3 s

The final velocity of the feather, v = ?

The equation of motion is given by the relation

                                    v = u + at

Substituting the values in the above equation

                                    v = 0 + 1.3 s · 1.62 m/s²

                                       = 2.106 m/s

Hence, the speed of the feather right before it hit the lunar surface is, v = 2.106 m/s

i already answered it by 34/s