Calculate and plot the total magnetic field intensity under a 500 kv transmission line. the balanced three-phase 500 kv transmission line phase conductors are arranged vertically at the same horizontal coordinate x0 = 15 ft. the phase conductors carrying 1000 a are located at heights of 80, 110, and 140 ft from ground level. determine the maximum h value at 1 m above ground level.

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.