An arrow is launched upward with an initial speed of 100 meters per second (m/s). the equations above describe the constant-acceleration motion of the arrow, where v₀ is the initial speed of the arrow, v is the speed of the arrow as it is moving up in the air, h is the height of the arrow above the ground, t is the time elapsed since the arrow was projected upward, and g is the acceleration due to gravity (9.8 m/s²).
what is the maximum height from the ground the arrow will rise to the nearest meter?

510 m

Explanation:

The arrow is fired upward, so the motion of the arrow is a free fall motion, therefore we can find the maximum height by using the suvat equation

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have:

v = 0 (at the point of maximum height, the velocity of the arrow is zero)

u = 100 m/s (initial velocity)

 (acceleration of gravity, downward)

s = ? is the maximum height

Solving for s,  we find the maximum height of the arrow:

are their multiple choices ?

explanation:

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles