Aproton (mass m 1.67 x 1027 kg) is being accelerated along a straight line at 1.4 x 1015 m/s2 in a machine. the proton has an initial speed of 2.4 x 107 m/s and travels 3.0 cm
(a) what is its speed? 25195237.6452 m/s
(b) what is the increase in its kinetic energy? 16366 ×

Part a)

Part b)

Explanation:

Part a)

As we know that proton is accelerated uniformly so we can use kinematics here to find the final speed

so we know that

so we will have

Part b)

Now increase in kinetic energy is given as

answer; /// i believe that the correct answer is (c)

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.