An electric power station that operates at 30 kv and uses a 20: 1 step-up ideal transformer is producing 330 mw (mega-watt) of power that is to be sent to a big city which is located 260 km away with only 2.5% loss. each of the two wires are made of copper (resistivity = 1.72×10^−8 ω.m). what is the diameter of the wires?

The diameter of the wire is 1.45cm

Explanation:

We can obtain the new voltage value using the transformer relationship:

Having the new voltage we can obtain the current value going through the wires:

We know that 2.5% of power is loss because the wire, so the power dissipated by the wires is:

The resistance value of the wire is given by:

We also know that:

answer; i believe the correct answer is (40,000 j) good luck

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