Acar weighing 10.1 kn and traveling at 11.5 m/s without negative lift attempts to round an unbanked curve with a radius of 65.0 m. (a) what magnitude of the frictional force on the tires is required to keep the car on its circular path?

a) 2095N

Explanation:

M = w/g = 10100/9.8 = 1.03 x 10^3 kg

Normal force = Gravitational force

Fn = M x g

Friction is

f = m x v^2 / r = 1.03 x 10^3 x (11.5)^2 / 65

F = 2.10 x 10^3 N

N/b to calculate maximum friction force,

Fmax = Us x mg

Fmax = Us x 10100N

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

friction

explanation:

they us to move forward and backwards