Arock is thrown horizontally at 10.0m/s off of a 150m sheer cliff. what is the range?

55.3 m

Explanation:

First, find how long it takes to land.

Given (in the y direction):

Δy = 150 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(150 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 5.53 s

Given (in the x direction):

v₀ = 10.0 m/s

a = 0 m/s²

t = 5.53 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (10.0 m/s) (5.53 s) + ½ (0 m/s²) (5.53 s)²

Δx = 55.3 m

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//