Ahorizontal force of 200 n is applied to move a 55 kg television set across a 10 m level surface. what is the work done by the 200 n force on the television set? a. 550 j c. 6000 j b. 2000 j d. 11000 j

2000J

Explanation:

Work done = force * distance

W = 200 * 10

W = 2000J

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s