Arock is thrown horizontally from a cliff at 25 m/s.
a) what will its horizontal and vertical velocities be after 2.0 s?
b) what will its velocity be (magnitude and direction) after 3.0 s?
c) what will its displacement be after 3.0 s?

a) horizontal: 25.0 m/s, vertical: -19.6 m/s

As the rock is thrown horizontally, it follows a parabolic motion (projectile motion), where:

- The horizontal motion is a uniform motion, with constant velocity

- The vertical motion is a uniformly accelerated motion, with constant acceleration towards the ground (we take upward as positive direction, so the acceleration is negative)

We said that the horizontal velocity is constant, so it remains equal to the velocity at which the rock was thrown from the cliff, therefore

And this is also the value of the horizontal velocity at t = 2.0 s.

Instead, the vertical velocity follows the equation

where:

is the initial vertical velocity

is the acceleration of gravity

t = 2.0 s is the time

Substituting,

b) 38.6 m/s at

In order to find the velocity at 3.0 s, we should find its horizontal and vertical components at that time first.

As we said, the horizontal velocity is constant:

while the vertical velocity is given by

And substituting t = 3.0 s,

The magnitude of the velocity at 3.0 s therefore is

While the direction is given by

where the negative sign means the angle is below the horizontal.

c) 87.0 m

In order to find the displacement, we should find the horizontal and vertical distance travelled by the rock in 3.0 s.

Along the horizontal direction, the motion is uniform, so the horizontal distance travelled is

While the distance travelled along the vertical direction is given by the equation

And substituting t = 3.0 s,

So, the displacement of the rock after 3.0 s is

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.