Adragster and driver together have mass 931.9 kg . the dragster, starting from rest, attains a speed of 25.7 m/s in 0.57 s. find the average acceleration of the dragster during this time interval. answer in units of m/s 2 .

45.09 m/s^2

Explanation:

from the question we were given the following parameters

mass = 931.9 kg

initial velocity (V1) = 0 m/s ( since it started from rest )

final velocity (V2) = 25.7 m/s

time (t) = 0.57 s

The average acceleration is given by:

a = ( V2 - V1 ) / t

therefore

a = (25.7 - 0) / 0.57 = 45.09 m/s^2

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000