A350 kg aircraft experiences a net force of 1184 n at take off.

a) what’s is the aircraft’s acceleration?

b) starting from rest, how fast will the aircraft be going after 10 seconds?

a)

The acceleration of the aircraft can be found by using Newton's second law:

where

F is the net force on the aircraft

m is the aircraft's mass

a is the acceleration

In this problem, we have

m = 350 kg

F = 1184 N

Re-arranging the equation for a, we find the acceleration of the plane:

b) 33.8 m/s

Since the motion of the aircraft is a uniform accelerated motion, we can use the following suvat equation

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the aircraft in the problem,

u = 0 (it starts from rest)

is the acceleration

Therefore, the velocity after t = 10 s is

what type of charge does it have? negative

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.