Find the minimum kinetic energy in mev necessary for an α particle to touch a 39 19 k nucleus that is initially at rest, assuming only coulomb forces are present. assume that the α particle has a radius of 2.0 fm, and the potassium nucleus of 3.7 fm, and take into account the masses of both particles.

KE = 9.6MeV

Explanation:

Given the relationships we understand that,

The Potential at point p, is given by the following formula

According to the graphic designed, you have,

The kinetic energy of the particle would be given by

the answer would be c. motion and direction

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