When you drop a 0.41 kg apple, earth exerts a force on it that accelerates it at 9.8 m/s 2 toward the earth’s surface. according to newton’s third law, the apple must exert an equal but opposite force on earth. if the mass of the earth 5.98 × 1024 kg, what is the magnitude of the earth’s acceleration toward the apple? answer in units of m/s 2 .

Explanation:

According to the second law of newton:-

Where, F is the force

m is the mass

a is the acceleration

For Apple:- Given that:

m = 0.41 kg

a = 9.8 m/s²

Thus,

This is the same force which the apple exerts on the Earth.

For Apple:- Given that:

m =

a = ?

Thus,

Earth’s acceleration toward the apple =

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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