The loop is in a magnetic field 0.20 t whose direction is perpendicular to the plane of the loop. at t = 0, the loop has area a = 0.285 square m. suppose the radius of the elastic loop increases at a constant rate, dr/dt = 3.70 cm/s .
a) determine the emf induced in the loop at t = 0.
b)determine the emf induced in the loop at t = 1.00 s .

Part a)

Part b)

Explanation:

As we know that magnetic flux through the loop is given as

now we have

now rate of change in flux is given as

now we know that

Now plug in all data

Part b)

Now the radius of the loop after t = 1 s

Now plug in data in above equation

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j