Based on the data collected, explain why a launch angle of 30 degrees (high horizontal velocity & small time of flight) will allow a projectile to go just as far when the launch angle of 60 degrees (low horizontal velocity and large time of flight).

Explanation:

The horizontal distance traveled by the projectile is given by the formula

The formula for the time of flight is given by

Case I: when the launch angle is 30°

So,

Horizontal velocity = u Cos 30 = 0.866 u

Case II: when the launch angle is 60°

Horizontal velocity = u Cos 60 = 0.5 u

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

d. air pressure decreases as altitude increases.