Auniform stick 1.5 m long with a total mass of 300 g is pivoted at its center. a 3.0-g bullet is shot through the stick midway between the pivot and one end the bullet approaches at 250 m/s and leaves at 140 m/s.
with what angular speed is the stick spinning after the collision?
ω= rad/s

2.2 rad/s

Explanation:

Given

Length of stick=1.5 m

mass m=300 gm

mass of bullet

approach velocity of bullet=250 m/s

Final Velocity of Velocity=140 m/s

Distance of Pivot to bullet hit is

Conserving Angular Momentum

Initial momentum

Moment of inertia of rod about Pivot

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m