Two circular loops of wire, each containing a single turn, have the same radius of 3.40 cm and a common center. the planes of the loops are perpendicular. each carries a current of 1.80 a. what is the magnitude of the net magnetic field at the common center?

To solve for the net magnetic field of two circular loops of wire, each containing a single turn

B net= √[( NUI / 2R)^2 × ( NUI / 2R)^2]

Where B net = Net magnetic field

B net = √2 × (NUI/ 2R)

B net =[ √2 × 1 × ( 4 × 3.142 × 10^-7) × (1.8)] ÷ 2 × 0.034

B net = { 1.414 × (0.00000126) × (1.8)}÷ 0.068

B net = 4.72 × 10^-5 T

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m