The propeller of a world war ii fighter plane is 2.30 m in diameter. (a) what is its angular velocity in radians per second if it spins at 1200 rev/min? (b) what is the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac? (c) what is the centripetal acceleration of the propeller tip under these conditions? calculate it in meters per second squared and convert to multiples of g .

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius=

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency=

1 minute=60 seconds

Angular velocity=

Angular velocity=

b.We have to find the linear speed of its tip at this  angular velocity if the plane is stationary on the tarmac.

c.Centripetal acceleration=

Centripetal acceleration==

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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