Atrunk of mass 16 kg is on the floor. the trunk has a very small initial speed. the acceleration of gravity is 9.8 m/s 2 . what constant horizontal force pushing thetrunk is required to give it a velocity of 10 m/s in 20 s if the coefficient of sliding friction between the trunk and the floor is 0.57? answer in units of n.

F=96 N

Explanation:

First of all, we need to calculate the acceleration, that's given by:

the problem states that the initial velocity is very small, so we can assume it as zero, so:

according to Newton's second law:

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2