Amineshaft has an ore elevator hung from a single braided cable of diameter 2.5 cm. young's modulus of the cable is 10×10^10n/m2. when the cable is fully extended, the end of the cable is 900 m below the support. how much does the fully extended cable stretch when 1500 kg of ore is loaded? express your answer with the appropriate unit

ΔL = 0.2697 m = 26.97 cm

Explanation:

Given

∅ = 2.5 cm = 0.025 m

E = 10*10¹⁰ N/m²

L = 900 m

m = 1500 Kg

ΔL = ?

We get P = W as follows

W = m*g = (1500 Kg)(9.81 m/s²) =  14715 N

then we apply the equation of Hooke's Law

ΔL = P*L / (A*E)

⇒  ΔL = 14715 N*900 m / (π*0.25*(0.025 m)²*10*10¹⁰ N/m²)

⇒  ΔL = 0.2697 m = 26.97 cm

d they tend to lose electrons and become cations.

explanation:

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.