A3.00 μf capacitor is charged to 480 v and a 4.00 μf capacitor is charged to 500 v . part a these capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the negative plates are connected to each other. what will be the potential difference across each capacitor?

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current