A0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 833 n/m). the other end of the spring is fixed in place, and the spring is unstrained initially. the block rests on a horizontal, frictionless surface. the bullet strikes the block perpendicularly and quickly comes to a halt within it. as a result of this completely inelastic collision, the spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.190 m. what is the speed of the bullet?

ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

= mass of the bullet = 0.0382 kg

= mass of wooden block = 3.78 kg

= velocity of the bullet-block combination after collision

= spring constant of the spring = 833 N m⁻¹

= Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of  bullet-block combination after collision = Spring potential energy gained due to compression of spring

ms⁻¹

= initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

ms⁻¹

the answer is a 3.8cm

explanation:

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000