An electron of mass 9.11×10-31kg leaves one end of a tv picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 1.30cm away. it reaches the grid with a speed of 2.50×106m/s . the accelerating force is constant.
a)find the acceleration.
b)find the time to reach the grid.
c)find the net force. (you can ignore the gravitational force on the electron).

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.